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cos⁡(x−257π2)=\cos(x - \frac{257\pi}{2}) = ?
cos⁡(x)\cos(x)
−sin⁡(2x)-\sin(2x)
−cos⁡(3x)-\cos(3x)
sin⁡(x)\sin(x)
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cos⁡(−3π2−a)=\cos(-\frac{3\pi}{2}-a)=?
sin⁡(a)\sin(a)
−sin⁡(2a)-\sin(2a)
−cos⁡(2a)-\cos(2a)
cos⁡(a)\cos(a)
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Soit ff telle que ∀x∈R\forall x \in \mathbf{R}, f(x)=cos⁡(4x)+2cos⁡(2x)f(x)=\cos(4x)+2\cos(2x). Alors :
ff est paire
f(π)=f(1)f(\pi)=f(1)
ff est décroissante sur[0,π] [0,\pi]
ff est impaire
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Soit ff telle que
∀x∈R\forall x \in \mathbf{R}, f(x)=−15sin⁡3(x)f(x)= - \frac{1}{5} \sin^3(x)
La dérivée de ff est :
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Limite de cos⁡(x)−1x \frac{\cos(x)-1}{x} quand x→0x\rightarrow0 ?
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Limite de sin⁡(x)x\frac{\sin(x)}{x} quand x→+∞x\rightarrow+\infty ?
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Limite de xsin⁡(1x)x\sin(\frac{1}{x}) quand x→+∞x\rightarrow +\infty ?
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Limite de xcos⁡(x)x\cos(x) quand x→+∞x\rightarrow +\infty ?
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Soit ff telle que ∀x∈R\forall x \in \mathbf{R}, f(x)=2cos⁡2(x)+3sin⁡(4x)f(x)=2\cos^2(x)+3\sin(4x). Alors :
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Quelles sont les solutions de
l'équation cos⁡2(x)=12\cos^2(x) = \frac{1}{2} ?
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